Closing the Exam Gap
Grade 6→7 to Grade 8→9
How to close the gap between mock and actual exam? Your chemistry knowledge is there. The gap is in how IGCSE exams ask questions — command words, mark-scheme precision, calculation technique, and scientific language.
| GAP TYPE | WHAT GRADE 6–7 STUDENTS DO | WHAT GRADE 8–9 ANSWERS DO | IGCSE EXAMPLE |
|---|---|---|---|
| 1. Vague language | Use general, imprecise words. Describe the right idea in the wrong words. | Use exact scientific vocabulary the mark scheme specifies. Know the difference between "clear" and "colourless", "halogen" and "halide ion". | Writing "the solution goes clear" when the mark scheme says "colourless" → 0 marks. Writing "a carboxylic acid is formed" when the mark scheme needs "ethanoic acid" → 0 marks. |
| 2. Incomplete explanations | Give half an explanation. State what happens without explaining why, or give the reason without linking to the consequence. | Every EXPLAIN question needs a cause → consequence chain. Two marks = two linked ideas. "Just stating it is unreactive" earns 0 if electrons are not mentioned. | "Explain why noble gases are unreactive." Grade 6–7: "They have a full outer shell." Grade 8–9: "They have a full outer shell, so they do not need to gain, lose, or share electrons to become stable." |
| 3. Calculation errors | Find moles correctly but skip the molar ratio from the equation, or forget to convert cm³ to dm³, or round incorrectly (writing 1.6 instead of 1.7). | Show every step. Use the equation's coefficients. Convert units. Round correctly to the specified significant figures. Even with a wrong first step, correct working earns error carried forward (ecf) marks. | In a titration: mol = (15 × 0.180) ÷ 1000 = 0.0027 mol H₂SO₄. Then × 2 for mole ratio to get KOH moles. Missing the ×2 loses the mark even if everything else is right. |
| 4. Chemical test answers | Give only the observation OR only the method. State "squeaky pop" without explaining how to test for the gas. Describe a flame test as "burning". | Structure: METHOD → OBSERVATION → CONCLUSION. Both the procedure and the result are needed. Examiners specifically note: "just giving the result is not enough". | "Describe a test for hydrogen gas." Grade 6–7: "Squeaky pop." Grade 8–9: "Hold a lit splint to the gas. A squeaky pop sound is heard, confirming hydrogen is present." |
| 5. Repeating the question | Write answers that restate the question stem or use the words given in the question. The examiner gives 0 marks for this. | Add NEW chemical information. Every mark point must go beyond what was already stated in the question. If the question says "proton acceptor", you cannot just write "it accepts protons". | Q: "H⁺ is described as a proton acceptor. Explain this." → Answer: "OH⁻ accepts protons" → 0 marks (too close to the stem). Correct: "H⁺ is a single proton (no electrons), and OH⁻ accepts this proton to form water." |
A: Orange-brown ✓ "Coloured" ✗ "Yellow" ✗
Q: "State what is meant by relative atomic mass."
A: The weighted mean mass of an atom compared to 1/12th the mass of a carbon-12 atom. ✓
A: Hold damp litmus paper to the gas. The paper first turns red, then is bleached white. ✓
Q: "Describe the trend in reactivity down Group I."
A: Reactivity increases going down the group — lithium is least reactive, caesium is most reactive. ✓
A: Sodium has more electron shells than lithium [1], so the outer electron is further from the nucleus [1] and is more easily lost/the shielding effect is greater [1].
Q: "Explain why noble gases are unreactive."
A (Grade 7): They have a full outer shell. [1/2]
A (Grade 9): They have a full outer shell, so they do not need to gain, lose, or share electrons. [2/2]
A: moles = concentration × volume (dm³)
= 0.1 × (25/1000) = 0.1 × 0.025 = 0.0025 mol ✓
Common trap: dividing by 100 instead of 1000 when converting cm³ → dm³.
A: Diamond has a giant covalent structure with strong covalent bonds throughout. A lot of energy is needed to break these bonds. ✓
Q: "Suggest why the rate of reaction decreases over time."
A: As reactants are used up, the concentration decreases, so there are fewer successful collisions per second. ✓
A: Fermentation uses renewable resources (sugar cane) and is cheaper [1], but produces impure ethanol needing further processing [1]. Hydration gives pure ethanol directly [1] but requires non-renewable crude oil and high temperature/pressure [1]. Overall, fermentation is more sustainable but hydration is more efficient industrially. [1]
A: The rate increases [1] because the particles have more kinetic energy, so there are more frequent collisions with energy greater than or equal to the activation energy [1]. ✓
Q: "Predict the colour of the precipitate formed when NaOH is added to Fe³⁺ ions."
A: Red-brown (rust-coloured) precipitate. ✓
State the electron configuration of sodium (atomic number 11) and say whether it forms a positive or negative ion.
Explain why sodium is more reactive than lithium. Use your knowledge of atomic structure in your answer. [3]
- Command word changed from STATE to EXPLAIN — now needs 3 connected ideas, not 1 fact
- Requires comparing TWO elements, not just describing one
- Students who write "sodium has more electrons" score 0/3 — must link to ease of losing the outer electron
- Full 3-mark answer: more electron shells [1] → outer electron further from nucleus / more shielding [1] → outer electron more easily lost [1]
What gas is produced when zinc reacts with dilute hydrochloric acid?
A student adds zinc to dilute hydrochloric acid and a gas is produced. Describe how the student could identify the gas. Include the method used, the observation, and what the observation shows. [3]
- Simply naming the gas (hydrogen) earns 0 — the question asks for the TEST, not the product
- Three separate mark points: method [1], observation [1], conclusion [1]
- Common grade 7 error: just writing "squeaky pop" — no method stated = 1/3 maximum
- Full answer: "Hold a lit splint to the gas [1]. A squeaky pop is heard [1]. This confirms the gas is hydrogen [1]."
Calculate the moles in 25 cm³ of 0.1 mol/dm³ NaOH solution.
In a titration, 15.0 cm³ of 0.180 mol/dm³ H₂SO₄ was used to neutralise 25.0 cm³ of KOH solution. H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O. Calculate the concentration of the KOH solution. Give your answer to 3 significant figures. [4]
- Now requires 4 steps: convert cm³ → dm³, find moles H₂SO₄, apply mole ratio (×2), find concentration KOH
- The most common error (2023 report): dividing by 100 instead of 1000 for the volume conversion
- Second most common error: ignoring the 1:2 molar ratio from the equation
- Specifying "3 significant figures" is a separate mark — writing 0.216 not 0.21600 matters
- Grade 9 rule: show every step on a new line. Errors carry forward only if working is visible
State two ways to increase the rate of a reaction between marble chips and hydrochloric acid.
A student investigates the reaction of marble chips with hydrochloric acid and plots a graph of mass lost against time. The graph levels off after 5 minutes. Explain, using collision theory, why the rate decreases as the reaction proceeds. [3]
- No longer asking what increases rate — asking WHY rate DECREASES (opposite direction, different thinking)
- "Using collision theory" is a constraint — answers without collision theory language earn 0
- 3-mark chain: acid concentration decreases [1] → fewer particles per unit volume [1] → fewer successful collisions per second [1]
- Grade 7 error: "the reaction slows because the acid runs out" — too vague, no collision theory, 0 marks
State one advantage and one disadvantage of making ethanol by fermentation.
Using information from the table (showing data about fermentation and hydration processes), evaluate the use of fermentation compared with hydration for the large-scale production of ethanol. [4]
- "State one advantage/disadvantage" → now requires using data from a table as evidence for each point
- An overall conclusion is ESSENTIAL for the final mark — students who list pros and cons without concluding always lose 1 mark
- Must use the data given ("as shown in the table, fermentation operates at 37°C vs 300°C for hydration") not just recalled facts
- Grade 9 answer structure: advantage + evidence [1], disadvantage + evidence [1], second point pair [1], conclusion [1]
| VAGUE (❌ loses mark) | PRECISE (✓ earns mark) | TOPIC |
|---|---|---|
| "goes clear" | "becomes colourless" | Solutions & precipitates |
| "a carboxylic acid forms" | "ethanoic acid forms" | Organic chemistry |
| "halogen" (when meaning ion) | "halide ion" | Halogens |
| "it reacts more" | "rate of reaction increases" | Rates |
| "particles hit each other more" | "frequency of successful collisions increases" | Collision theory |
| "it's burning" | "it's a flame test" (flame tests are NOT combustion) | Flame tests |
| "the atom is stable" | "the atom has a full outer shell of electrons" | Bonding / reactivity |
| "gets hotter / exothermic" | "heat is released to the surroundings / temperature of surroundings increases" | Energy changes |
| "sodium sulphide" | "Na₂S" — a compound ending in -ide has no oxygen | Formulae / naming |
| MARK | WHAT IS BEING ASSESSED | COMMON ERROR |
|---|---|---|
| M1 | Correct conversion of cm³ to dm³ (÷1000) | Dividing by 100 instead of 1000 |
| M2 | Correct moles calculation (mol = conc × vol) | Multiplying instead of dividing, or inverted calculation |
| M3 | Applying the molar ratio from the balanced equation | Ignoring the ratio (e.g. 1:2 ratio → must ×2 for moles of KOH) |
| M4 | Correct final answer to specified significant figures | Rounding 1.67 → 1.6 (wrong) instead of 1.7 (correct to 2 sf) |
- 1State the structural/bonding difference: "Compared to [X], [Y] has [more/fewer/stronger] [shells/bonds/electrons/forces]..."[M1]
- 2Link to the chemical reason: "...therefore the outer electron is [further/closer] from the nucleus / the forces are [stronger/weaker] because..."[M2]
- 3State the consequence for the property asked about: "...so [Y] [melts at a higher temperature / reacts more vigorously / is more reactive] than [X]."[M3]
- 1State the reagent: "Add [exact reagent name and form] to the sample." — Never just say "add acid". Name it specifically.[M1]
- 2State the observation: "A [colour] precipitate forms / [colour] flame is seen / the solution [becomes colourless / turns cloudy]." Be precise — not "changes colour" but the exact colour.[M2]
- 3State the conclusion: "This confirms the presence of [ion/gas/element] because..." — Link the observation to what it proves.[M3]
- ★BEFORE calculating: Write the balanced equation. Write volumes/concentrations under each formula. Note the molar ratio. Check what unit the answer needs. This takes 30 seconds and prevents all common errors.0
- 1Convert units: cm³ ÷ 1000 = dm³. Write: "Volume = X cm³ ÷ 1000 = Y dm³"[M1]
- 2Calculate moles of the known substance: "moles = concentration × volume = ... = Z mol". Show the multiplication.[M2]
- 3Apply molar ratio: "From the equation, mole ratio = 1:2. Moles of [target] = Z × 2 = ..."[M3]
- 4Calculate the final answer with correct units and correct sig figs/decimal places: "concentration = moles ÷ volume = ... mol/dm³ (to 3 s.f.)"[M4]
- 1State Advantage 1 of method A: "An advantage of [process A] is [X]..."[M1]
- 2Explain WHY it's an advantage: "...because this means [economic/environmental/practical benefit]."[M2]
- 3State Disadvantage with reason: "However, a disadvantage is [Y] because [reason]."[M3]
- 4Reference the data given: "As shown in the table/graph, [quote specific value or piece of data]..."[M4]
- 5Overall conclusion (ESSENTIAL — always lost by grade 6–7 students): "Overall, [method A/B] is more suitable because [balanced judgment referencing your evidence]."[M5]
- 1State what changes about the particles: "Increasing [temperature/concentration/surface area] means particles have [more kinetic energy / are more crowded / have more surface area exposed]..."[M1]
- 2Link to collision frequency: "...therefore the frequency of collisions between particles increases..."[M2]
- 3Link to successful collisions: "...and more collisions have energy greater than or equal to the activation energy, so the rate of reaction increases."[M3]
